Цикл с условием

Бейсик

Python

DIM N, S AS INTEGER

N = 0

S = 0

WHILE S <= 221

S = S + 11

N = N + 1

WEND

PRINT N

n = 0

s = 0

while s <= 221:

s = s + 11

n = n + 1

print(n)

Алгоритмический язык

Паскаль

алг

нач

цел n, s

n := 0

s := 0

нц пока s <= 221

s := s + 11

n := n + 1

кц

вывод n

кон

var n, s: integer;

begin

n := 0;

s := 0;

while s <= 221 do

begin

s := s + 11;

n := n + 1

end;

write(n)

end.

С++

#include <iostream>

using namespace std;

void main()

{

int n, s;

n = 0;

s = 0;

while (s <= 221)

{

s = s + 11;

n = n + 1;

}

cout << n << endl;

}